Recognizing congruent shapes
Recognizing congruent shapes
There are two congruent right triangles, $\triangle LMN$ and $\triangle XYZ$, shown with green fill and marked right angles. The triangles are congruent, meaning they have identical shape and size.
In these congruent triangles:
In congruent figures, all corresponding sides and angles are equal. Therefore, triangles $LMN$ and $XYZ$ have:
Angles are named using three letters:
Use tracing paper to check for congruence.
1. Which triangles are congruent to triangle A?
2. Which shapes are congruent to shape A?
3. Rectangle ABCD is congruent to rectangle EFGH.
a. Find the length of side AB.
b. Calculate the area of rectangle ABCD.
a. $AB = 5$ cm
b. Area = $AB \times BC = 5 \times 3 = 15$ cm²
4. Triangles $\triangle ABC$ and $\triangle DEF$ are congruent.
a. Write the lengths of the sides of $\triangle ABC$.
b. Write the sizes of the angles of $\triangle ABC$.
c. Write the lengths of the sides of $\triangle DEF$.
d. Write the sizes of the angles of $\triangle DEF$.
a. $AB = 13$ cm, $BC = 12$ cm, $AC = 5$ cm
b. $\angle A = 35^\circ$, $\angle B = 55^\circ$, $\angle C = 90^\circ$
c. $DE = 13$ cm, $EF = 12$ cm, $DF = 5$ cm
d. $\angle D = 35^\circ$, $\angle E = 55^\circ$, $\angle F = 90^\circ$
5. Triangles $\triangle UVW$ and $\triangle XYZ$ are congruent.
a. Write the lengths of the sides of $\triangle UVW$.
b. Write the sizes of the angles of $\triangle XYZ$.
a. $UV = 7$ cm, $VW = 24$ cm, $UW = 25$ cm
b. $\angle X = 90^\circ$, $\angle Y = 73.7^\circ$, $\angle Z = 16.3^\circ$
6. Sofia drew two triangles. Are they congruent?
Question: In an equilateral triangle all the angles are 60°. This means that all equilateral triangles must be congruent, as all the angles are the same size. Is it correct? Discuss.
Equipment: Paper, pencil, ruler, protractor
Method:
Follow-up Questions:
For congruence, check if all corresponding sides and angles are equal. Remember: SSS (Side-Side-Side) is a valid congruence criterion.
8. Two triangles are shown with side lengths:
Triangle 1: $5.3$ cm, $7.1$ cm, $9.5$ cm
Triangle 2: $7.1$ cm, $5.3$ cm, $9.5$ cm
a. Sofia says the triangles are congruent because corresponding sides are equal. Zara disagrees, saying we need to know the angles. Who is correct? Explain your reasoning.
b. Arun mentions that congruent shapes have the same perimeter. Calculate the perimeter of each triangle and explain how this relates to congruence.
a. Sofia is correct. By the SSS (Side-Side-Side) congruence criterion, if all three sides of one triangle are equal to the corresponding sides of another triangle, then the triangles are congruent. The angles are not needed to establish congruence in this case.
b. Perimeter of Triangle 1 = $5.3 + 7.1 + 9.5 = 21.9$ cm
Perimeter of Triangle 2 = $7.1 + 5.3 + 9.5 = 21.9$ cm
Since the triangles are congruent, they have identical perimeters. Congruent shapes always have the same perimeter because all corresponding sides are equal.
9. Explain why knowing only the side lengths is sufficient to determine congruence in this case, but might not be sufficient in other cases.
10. Classify these shapes into groups. Describe the properties that characterise each of your groups.
Group 1: Circles (A, I, L)
Properties: Round shape with no straight sides or angles. All points are equidistant from the center. No vertices.
Group 2: Triangles (C, D, F, G, K, M)
Properties: Three straight sides and three angles. Sum of interior angles is $180^\circ$. Can be classified by side lengths (equilateral, isosceles, scalene) or angles (acute, right, obtuse).
Group 3: Squares and Rectangles (B, N, P)
Properties: Four sides and four right angles ($90^\circ$). Opposite sides are equal and parallel. Squares have all sides equal; rectangles have opposite sides equal. Sum of interior angles is $360^\circ$.
Group 4: Hexagons (E, J)
Properties: Six straight sides and six angles. Sum of interior angles is $720^\circ$. Can be regular (all sides and angles equal) or irregular.
Group 5: Trapezoids (H, Q)
Properties: Four sides with exactly one pair of parallel sides. The parallel sides are called bases. Sum of interior angles is $360^\circ$.