Stem-and-leaf diagrams
Stem-and-leaf diagrams
A stem-and-leaf diagram is a way of showing data in order of size.
When you draw a stem-and-leaf diagram, make sure:
2 | 3 4 7 8 |
3 | 0 6 7 7 8 |
4 | 1 9 9 |
Key: 2 | 3 means 23 cm
1. Shen listed the playing times, to the nearest minute, of some CDs. He recorded the results in a stem-and-leaf diagram.
Key | 4 | 5 means 45 minutes |
---|---|
4 | | 5 5 7 9 |
5 | | 0 2 5 6 8 9 |
6 | | 1 2 4 6 7 |
a) How many CDs did Shen list?
b) What is the shortest playing time?
c) How many of the CDs had a playing time longer than 60 minutes?
d) Work out
i) the mode ii) the median iii) the range of the data.
a) 15 CDs (there are 4 + 6 + 5 leaves).
b) 45 minutes (leaf 5 on stem 4).
c) 5 CDs (all on stem 6: 61, 62, 64, 66, 67).
d)
i) Mode: 45 minutes (appears twice; all others once).
ii) Median: 56 minutes (8th value of 15 in order).
iii) Range: 67 − 45 = 22 minutes.
Task: Analyse a stem-and-leaf diagram showing the number of cups of coffee sold each day in one month. Work out missing details and answer questions about the data.
Stem-and-leaf diagram:
11 | | 2 4 6 8 |
12 | | 0 0 1 2 4 5 6 9 |
13 | | 1 4 4 5 8 9 |
14 | | 2 7 7 7 |
15 | | 0 1 1 3 6 8 |
Key: 12 | 4 means 124 cups of coffee.
Questions:
3. These are the file sizes, in kilobytes (kB), of 30 files on Greg’s computer.
101 | 128 | 117 | 109 | 154 | 139 | 166 | 155 | 117 | 145 | 135 | 162 | 117 | 168 | 125 |
131 | 140 | 160 | 151 | 125 | 152 | 108 | 139 | 130 | 165 | 158 | 103 | 130 | 110 | 148 |
a) Draw an ordered stem-and-leaf diagram to show this data.
b) How many of the files are larger than 150 kB?
c) Which average, the mode or the median, better represents this data? Explain why.
d) Greg works out that the range in his file sizes is 65 kB. Is Greg correct? Explain your answer.
a) Ordered stem-and-leaf (tens as stems, ones as leaves). Key: 10 | 1 means 101 kB.
10 | | 1 3 8 9 |
11 | | 0 7 7 7 |
12 | | 5 5 8 |
13 | | 0 0 1 5 9 9 |
14 | | 0 5 8 |
15 | | 1 2 4 5 8 |
16 | | 0 2 5 6 8 |
b) 10 files are larger than 150 kB (151, 152, 154, 155, 158, 160, 162, 165, 166, 168).
c) The median is a better measure of average for this set because the data are spread across a wide range and the mode (117 kB) is not representative of the centre. The median is 137 kB (the mean of the 15th and 16th ordered values, 135 and 139).
d) Greg is not correct. The range is max − min = 168 − 101 = 67 kB, not 65 kB.
Task: Decide if Opaline’s method is correct and suggest the best way to calculate the mean from a stem-and-leaf diagram.
Scenario: Opaline counted the number of birds in her garden each day for 10 days. She recorded the results in a stem-and-leaf diagram:
0 | | 4 8 9 |
1 | | 2 4 9 |
2 | | 0 2 3 7 |
Key: 0 | 4 means 4 birds.
Opaline’s method: She worked out the mean of each row separately, then averaged those results. She got 15 birds as the overall mean.
Questions:
5. Ashish counted the number of cars passing his school between 8.30 a.m. and 9 a.m. each day for 12 days. The stem-and-leaf diagram shows his results. Key: 0 | 1 means 1 car.
0 | | 1 2 3 6 7 7 9 |
1 | | 7 |
2 | | 0 4 4 4 |
a) Use the stem-and-leaf diagram to work out
i) the mode ii) the median iii) the mean of the data.
b) Which average, the mode, median or mean, best represents this data? Explain why.
a)
i) Mode: 24 (appears three times).
ii) Median: order gives 1,2,3,6,7,7,9,17,20,24,24,24 → median is average of 6th and 7th = (7+9)/2 = 8.
iii) Mean: sum = 144, number of days = 12 → mean = 12 cars.
b) The median (8) best represents a typical day because the mean is pulled up by the three high values (24) and the mode 24 is not typical of most days.
6. The students in class 8B took a test (out of 40). The stem-and-leaf diagram shows their scores. Key: 1 | 8 means 18.
0 | | 6 8 8 9 9 |
1 | | 6 |
2 | | 5 6 8 8 9 |
3 | | 0 1 2 3 5 6 7 8 8 |
4 | | 0 0 0 |
a) What percentage of the students had a score greater than 32?
b) What fraction of the students had a score less than 25%?
c) Any student scoring less than 40% must re-sit the test. How many students do not have to re-sit the test?
Total students = 23.
a) Scores > 32 are 33, 35, 36, 37, 38, 38, 40, 40, 40 → 9 students → percentage ≈ 39%.
b) 25% of 40 is 10. Scores < 10 are 6, 8, 8, 9, 9 → 5/23 of the class.
c) 40% of 40 is 16. Students with scores < 16 are the same 5 listed above, so students who do not re-sit = 23 − 5 = 18.