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Last update: 2022-10-11
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Physics A Level

Chapter 10: Resistance and resistivity 10.1 The I-V characteristic for a metallic conductor

Physics A Level

Chapter 10: Resistance and resistivity 10.1 The I-V characteristic for a metallic conductor

2022-10-11
94
Crash report

 Physics (9702)

In Chapter 8, we saw how we could measure the resistance of a resistor using a voltmeter and ammeter. In this topic we are going to investigate the variation of the current – and, therefore, resistance – as the potential difference across a conductor changes.
The potential difference across a metal conductor can be altered using a variable power supply or by placing a variable resistor in series with the conductor. This allows us to measure the current at different potential differences across the conductor. The results of such a series of measurements are shown graphically in Figure 10.2.

Figure 10.2: To determine the resistance of a component, you need to measure both current and
potential difference.

Look at the graph of Figure 10.2. Such a graph is known as an I–V characteristic. The points are slightly scattered, but they clearly lie on a straight line. A line of best fit has been drawn. You will see that it passes through the origin of the graph. In other words, the current I is directly proportional to the voltage V.
The straight-line graph passing through the origin shows that the resistance of the conductor remains constant. If you double the current, the voltage will also double. However, its resistance, which is the ratio of the voltage to the current, remains the same. Instead of using:

$R = \frac{V}{I}$

to determine the resistance, for a graph of I against V that is a straight line passing through the origin, you can also use:

$resistance\, = \,\frac{1}{{gradient\,of\,graph}}$

(This will give a more accurate value for R than if you were to take a single experimental data point. Take care! You can only find resistance from the gradient if the I–V graph is a straight line through the origin.)
By reversing the connections to the resistor, the p.d. across it will be reversed (in other words, it becomes negative). The current will be in the opposite direction – it is also negative. The graph is symmetrical, showing that if a p.d. of, say, $2.0 V$ produces a current of $0.5 A$, then a p.d. of $−2.0 V$ will produce a current of $−0.5 A$. This is true for most simple metallic conductors but is not true for some electronic components, such as diodes.
You get results similar to those shown in Figure 10.2 for a commercial resistor. Resistors have different resistances, so the gradient of the I–V graph will be different for different resistors.

Question

 

1) Table 10.1 shows the results of an experiment to measure the resistance of a carbon resistor whose resistance is given by the manufacturer as $47\,\Omega  \pm 10\% $.
a: Plot a graph to show the I–V characteristic of this resistor.
b: Do the points appear to fall on a straight line that passes through the origin of the graph?
c: Use the graph to determine the resistance of the resistor.
d: Does the value of the resistance fall within the range given by the manufacturer?

Table 10.1: Potential difference V and current I

Potential difference / V Current / A
2.1 0.040
4.0 0.079
6.3 0.128
7.9 0.192
10.0 0.202
12.1 0.250