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Multiplying decimals booklet

Multiplying decimals booklet

calendar_month 2025-08-14
visibility 83
bug_report Crash report
  • Unit 1: Integers
  • Unit 2: Place value & Rounding
  • Unit 3: Decimals
  • Unit 4: Fractions
  • Unit 5: Percentages
  • Unit 6: Ratio & Proportion

🎯 In this topic you will

  • Multiply decimals by whole numbers and decimals
 

🧠 Key Words

  • estimation
  • fill in
  • mentally
  • place value
  • written method
Show Definitions
  • estimation: Finding an approximate value close to the exact answer.
  • fill in: To complete missing parts of a number, statement, or calculation.
  • mentally: Solving a calculation in your head without writing it down.
  • place value: The value of a digit depending on its position in a number.
  • written method: A step-by-step calculation recorded on paper or digitally.
 

Follow these steps when you multiply a decimal by a whole number:

  • First, work out the multiplication without the decimal point.
  • Finally, put the decimal point in the answer. There must be the same number of digits after the decimal point in the answer as there were in the question.
 
📘 Worked example

a. Work these out mentally.
i. $0.002 \times 4$  ii. $30 \times 0.06$

b. Use a written method to work out $476 \times 3.7$.

Answer:

a. i.
$2 \times 4 = 8$
$0.002 \times 4 = 0.008$

a. ii.
$30 \times 6 = 180$
$30 \times 0.06 = 1.80$
$30 \times 0.06 = 1.8$

b.

4 7 6 × 3 7 ──────── 3 3 3 2 1 4 2 8 0 ────────── 1 7 6 1 2

$476 \times 3.7 = 1761.2$

a. i. Do the multiplication without the decimal point. Then put the decimal point back in the answer. There are three digits after the decimal in the question, so the answer must have three digits after the decimal: $0.008$.

a. ii. Do the multiplication without the decimal point. Then place the decimal back in the answer. There are two digits after the decimal point in the question, so there must be two digits after the decimal point in the answer: $1.80$. You can write $1.80$ as $1.8$ because the trailing zero is not needed.

b. Do the multiplication without the decimal point. Use any standard written method:
Work out $476 \times 7 = 3332$.
Work out $476 \times 30 = 14280$.
Add the partial products: $3332 14280 = 17612$.
Put the decimal point back into the answer: since $3.7$ has one decimal place, $476 \times 3.7 = 1761.2$.

 

🧠 PROBLEM-SOLVING Strategy

Multiply Decimals by Whole Numbers & Decimals

Multiply as whole numbers, then place the decimal using total decimal places in the factors; use estimation to sense-check.

Mental methods
  1. Ignore decimals, multiply, then replace the decimal — count decimal places across all factors and place that many in the product.
    Example: $0.002\times4$$2\times4=8$ with 3 d.p. → $0.008$.
  2. Use powers of ten — rewrite decimals via $10^{k}$:
    $30\times0.06=(3\times10)\times(6\times10^{-2})=18\times10^{-1}=1.8$.
  3. Round & adjust — round a factor to make mental multiplication easy, then correct.
    Example: $3.7\times476\approx4\times476=1904$, adjust by $-0.3\times476= -142.8$$1761.2$.
Written method
  1. Drop decimals, multiply as whole numbers — use column/long multiplication with partial products.
  2. Replace the decimal point — total decimal places in answer = sum of decimal places in the factors.
  3. Estimate first — round to check reasonableness of the exact product.

Quick examples

  • $0.002\times4=0.008$
  • $30\times0.06=1.8$
  • $476\times3.7$ → compute $476\times37$ then place 1 d.p. → $1761.2$
  • $6\times0.04=0.24$ (two decimal places in the product)
 

EXERCISES

1. Use a mental method to work out the following.

a) $0.1 \times 8$

b) $0.5 \times 5$

c) $0.9 \times 2$

👀 Show answer
a) $0.1\times 8=\boxed{0.8}$
b) $0.5\times 5=\boxed{2.5}$
c) $0.9\times 2=\boxed{1.8}$

2. Use a mental method to work out the following. All the answers are shown in the cloud.

a) $6\times 0.02$

b) $4\times 0.3$

c) $3\times 0.004$

d) $120\times 0.1$

Answer cloud with 12, 1.2, 0.12, 0.012

👀 Show answer
a) $6\times 0.02=\boxed{0.12}$  b) $4\times 0.3=\boxed{1.2}$  c) $3\times 0.004=\boxed{0.012}$  d) $120\times 0.1=\boxed{12}$

3. Copy this diagram and fill in the missing numbers. All the calculations give the answer in the centre oval. All the missing numbers are given in the rectangle.

Spoke diagram centred on 2.4 with blanks and a number bank

👀 Show answer
Each spoke must equal $2.4$. Fill the blanks with numbers from the rectangle: $8\times 0.3$ (given), $40\times \boxed{0.06}$, $\boxed{30}\times 0.08$, $\boxed{12}\times 0.2$, $4\times \boxed{0.6}$, $\boxed{24}\times 0.1$, $2\times \boxed{1.2}$, $\boxed{6}\times 0.4$.

4. Kai works out that $521\times 53=27613$. Use this information to write down the answer to the following.

a) $521\times 5.3$

b) $521\times 0.53$

👀 Show answer
Since $53=10\times 5.3=100\times 0.53$: a) $521\times 5.3=\dfrac{27613}{10}=\boxed{2761.3}$
b) $521\times 0.53=\dfrac{27613}{100}=\boxed{276.13}$
 

🧠 Think like a Mathematician

Question:

  1. a) What is the answer to $52.1 \times 53$? What do you notice about this answer and the answer to part a of Question 4?
  2. b) Why is the answer to $521 \times 0.53$ the same as the answer to $5.21 \times 53$?

Follow-up prompts:

1. How does moving the decimal point affect multiplication results?
2. How can you use place value and scaling to explain the relationship between these products?
👀 show answer
  • a:$52.1 \times 53 = 2761.3$. This answer is exactly 10 times the answer to $5.21 \times 53$ because 52.1 is 10 times larger than 5.21.
  • b:$521 \times 0.53 = (521 \times 53) \div 100$ and $5.21 \times 53 = (521 \times 53) \div 100$. Both involve multiplying 521 by 53 and then dividing by 100, so the results are identical.
  • Key idea: Moving the decimal point in one factor changes the size of the number by a power of ten, which you can compensate for in the other factor to keep the product the same.
 

EXERCISES

6. a) Work out $162\times 34$.

b) Use your answer to part a to write down the answers to the following.

i) $162\times 3.4$   ii) $162\times 0.34$   iii) $162\times 0.034$
iv) $16.2\times 34$   v) $1.62\times 34$   vi) $0.162\times 34$

👀 Show answer
a) $162\times 34=162(30 4)=4860 648=\boxed{5508}$.

b) Scale by powers of $10$ from part a: i) $162\times 3.4=\dfrac{5508}{10}=\boxed{550.8}$  ii) $\dfrac{5508}{100}=\boxed{55.08}$  iii) $\dfrac{5508}{1000}=\boxed{5.508}$
iv) $16.2\times 34=\dfrac{5508}{10}=\boxed{550.8}$  v) $\dfrac{5508}{100}=\boxed{55.08}$  vi) $\dfrac{5508}{1000}=\boxed{5.508}$

7. Raj uses these methods to work out and check his answer.

Raj's grid method for $0.45\times372$ and rounding check

a) Write down the advantages and disadvantages of Raj’s method.

b) Can you improve his method?

👀 Show answer
a)Advantages: The grid/partition method keeps place value clear and is reliable; converting $0.45\times372$ to $45\times372$ then dividing by $100$ gives the exact result $167.4$. The rounding check ($0.5\times400=200$) sensibly estimates size.
Disadvantages: The grid uses many partial products (time‑consuming); the rounding check is crude—$200$ is quite far from $167.4$, so it doesn’t tightly validate the answer.

b) Possible improvements (any one of the following, with working):
• Use compensation: $0.45=0.5-0.05$, so $0.45\times372=(0.5\times372)-(0.05\times372)=186-18.6=\boxed{167.4}$. • Scale first to reduce steps: $372\times45=\boxed{16740}$ then divide by $100\Rightarrow \boxed{167.4}$ (do $372\times(40 5)=14880 1860=16740$). • Use $4.5\times37.2$ (both ×$10$ then ÷$100$): $4.5\times37.2=(4.5\times30) (4.5\times7.2)=135 32.4=\boxed{167.4}$. • Tighter check: round to $0.45\times370=166.5$ or $0.45\times380=171$; $167.4$ lies reasonably between these.

8. Work out these multiplications. Show how to check your answers.

🔎 Reasoning Tip

Checking your work: For the check for part c, work out \( 0.8 \times 40 \).

a) $3.2 \times 52$

b) $8.1 \times 384$

c) $0.78 \times 41$

👀 Show answer
a) $3.2 \times 52 = 3.2 \times (50 2) = 160 6.4 = \boxed{166.4}$ Check: $3.2 \approx 3$, $3 \times 52 = 156$ (close to $166.4$).

b) $8.1 \times 384 = 8.1 \times (400 - 16) = 3240 - 129.6 = \boxed{3110.4}$ Check: $8 \times 384 = 3072$ (close to $3110.4$).

c) $0.78 \times 41 = 0.78 \times (40 1) = 31.2 0.78 = \boxed{31.98}$ Check: $0.8 \times 41 = 32.8$ (close to $31.98$).

9. This is part of Anna’s homework.

Anna's lattice method for 47.35 × 18

a) Without checking the method and working out the answer, how can you tell that Anna is incorrect?

b) Work out the correct answer, showing all your working.

👀 Show answer
a) The answer $85.23$ is clearly too small: $47.35 \approx 50$, and $50\times 18 = 900$, so the result should be in the hundreds, not below $100$.

b) Step 1: Ignore the decimal: $4735\times 18$ $4735 \times 10 = 47350$ $4735 \times 8 = 37880$ Sum: $47350 37880 = 85230$
Step 2: Adjust for two decimal places in $47.35$: $85230 \div 100 = \boxed{852.30}$ So the correct answer is $\mathbf{852.3}$.

10. In 1 gram of green gold there is 0.23 g of copper.
How many grams of copper are there in 36 g of green gold?

👀 Show answer
Copper per gram: $0.23\ \text{g}$. For $36$ g: $36\times 0.23 = \boxed{8.28\ \text{g}}$ of copper.

11. Darren exchanges some British pounds (£) to US dollars ($).
For every £1 he receives $1.29.
Darren says, ‘If I exchange £275, I should receive about $350.’
Is Darren correct? Explain your answer.

👀 Show answer
$£275\times 1.29 = 275\times 1.29 = \boxed{\$354.75}$. Darren’s estimate of about $350 is reasonable — he slightly underestimated by $\$4.75$.

12. Samir manages a hotel. The table shows the cost of items that he buys for the hotel bathrooms.

Table of item costs for shampoo, shower gel, hand lotion, and soap

Samir buys:
• 350 bottles of shampoo
• 425 bottles of shower gel
• 275 bottles of hand lotion
• 600 bars of soap.
What is the total cost of these items?

👀 Show answer
Shampoo: $350\times 0.26 = 91.00$ Shower gel: $425\times 0.23 = 97.75$ Hand lotion: $275\times 0.32 = 88.00$ Soap: $600\times 0.18 = 108.00$
Total cost: $91 97.75 88 108 = \boxed{\$384.75}$.
 

🍬 Learning Bridge

Now that you can confidently multiply decimals by whole numbers and decimals using place value, you’re ready to take it a step further. Next, you’ll apply the same skills to situations with negative numbers and more varied decimal combinations — where understanding signs, place value, and estimation becomes even more important for getting accurate results.

 

Follow these steps when you multiply a decimal by a whole number or a decimal:

  • First, work out the multiplication without the decimal points.
  • Finally, put the decimal point in the answer. There must be the same number of digits after the decimal point in the answer as there were in the question.
 
📘 Worked example

a. Work out mentally

i. $0.02 \times -12$  ii. $3.2 \times 0.04$

b. Use a written method to work out $5.96 \times 0.35$.
Check your answer using estimation.

Answer:

a. i.
$2 \times -12 = -24$
$0.02 \times -12 = -0.24$

a. ii.
$32 \times 4 = 128$
$3.2 \times 0.04 = 0.128$

b.

5 9 6 × 3 5 ──────── 2 9 8 0 1 7 8 8 0 ────────── 2 0 8 6 0

$5.96 \times 0.35 = 2.0860$
$5.96 \times 0.35 = 2.086$

Check
$6 \times 0.4 = 2.4 \ \checkmark$

a. i. Do the multiplication without the decimal points. Put the decimal point back in the answer. There are $2$ digits after the decimal in the question, so the answer must have $2$ digits after the decimal.

a. ii. Do the multiplication without the decimal points. Put the decimal point back in the answer. There are $3$ digits in total after the decimal points in the question, so the answer must have $3$ digits after the decimal.

b. Do the multiplication without the decimal points using your preferred written method:
Work out $596 \times 5 = 2980$.
Work out $596 \times 30 = 17880$.
Add the two results: $2980 17880 = 20860$.
Put the decimal point back in — there are $4$ digits in total after the decimal points in the question, so the answer must have $4$ digits after the decimal point: $2.0860$ → $2.086$ (ignore trailing zero).

Estimation: Round both numbers to one significant figure: $6 \times 0.4 = 2.4$, which is close to $2.086$, so the answer is probably correct.

 

🧠 PROBLEM-SOLVING Strategy

Multiply Decimals by Whole Numbers or Decimals (Including Negatives)

Multiply without the decimal points first, then replace them based on the total decimal places in the question.

  1. Ignore decimal points — multiply the numbers as if they are whole numbers.
  2. Count decimal places — add the decimal places from all factors.
  3. Place the decimal point — ensure the product has the same total decimal places as the question.
  4. Apply the sign:
    • Same sign → product is positive.
    • Different signs → product is negative.
  5. Estimate to check — round to 1 significant figure, multiply, and compare to the exact answer.
  6. Sense-check:
    • Both factors < 1 → product smaller than each factor.
    • One factor < 1 → product smaller than the larger factor.
    • Factor = 0 → product is 0.

Quick examples

  • $0.02\times(-12)$$2\times12=24$ → 2 d.p. → $-0.24$
  • $3.2\times0.04$$32\times4=128$ → 3 d.p. → $0.128$
  • $5.96\times0.35$$596\times35=20860$ → 4 d.p. → $2.086$
 

EXERCISES

13. Use a mental method to work out:

a) $0.1 \times (-8)$

b) $0.2 \times 3$

c) $0.3 \times (-7)$

d) $0.7 \times 8$

e) $0.9 \times (-4)$

👀 Show answer
a) $0.1 \times (-8) = -0.8$
b) $0.2 \times 3 = 0.6$
c) $0.3 \times (-7) = -2.1$
d) $0.7 \times 8 = 5.6$
e) $0.9 \times (-4) = -3.6$

14. Use a mental method to work out:

a) $-6 \times 0.03$

b) $-9 \times 0.2$

c) $-18 \times 0.001$

d) $-20 \times 0.9$

Answer cloud with -18, -0.18, -1.8, -0.018

👀 Show answer
a) $-6\times 0.03 = \boxed{-0.18}$
b) $-9\times 0.2 = \boxed{-1.8}$
c) $-18\times 0.001 = \boxed{-0.018}$
d) $-20\times 0.9 = \boxed{-18}$

15. Here are five calculation cards:

Five calculation cards A–E with decimal multiplications

a) Work out the answers to the calculations on the cards.
b) Write the answers in order of size, starting with the smallest.

👀 Show answer
A) $0.6\times (-12) = -7.2$
B) $0.039\times (-180) = -7.02$
C) $0.85\times (-9) = -7.65$
D) $0.44\times (-16) = -7.04$
E) $0.04\times (-182) = -7.28$

Order from smallest to largest: $-7.65$ (C), $-7.28$ (E), $-7.2$ (A), $-7.04$ (D), $-7.02$ (B)
 

🧠 Think like a Mathematician

Scenario: Arun says: “I don’t understand why $0.2 \times 0.3$ is $0.06$ and not $0.6$.”

Zara shows Arun this pattern:

  • $2 \times 3 = 6$
  • $0.2 \times 3 = 0.6$
  • $0.2 \times 0.3 = 0.06$
  • $0.2 \times 0.03 = 0.006$
  • $0.2 \times 0.003 = 0.0006$

Question: How can you use the place value of the digits in 0.2 and 0.3 to explain to Arun why the answer is 0.06 and not 0.6?

Follow-up prompts:

1. How does multiplying by a number less than 1 affect the size of the answer?
2. How does writing the numbers as fractions help in understanding this calculation?
👀 show answer
  • Explanation: - $0.2 = \dfrac{2}{10}$ and $0.3 = \dfrac{3}{10}$. - Multiplying: $\dfrac{2}{10} \times \dfrac{3}{10} = \dfrac{6}{100}$. - $\dfrac{6}{100} = 0.06$.
  • Each factor has one decimal place, so in the product you must have two decimal places in total. This is why 0.2 × 0.3 gives 0.06, not 0.6.
  • Key idea: Multiplying by a decimal less than 1 reduces the value, not increases it.
 

EXERCISES

17. a) Copy and complete these patterns.

i $2\times 4 = 8$

$0.2\times 4 = \_\_\_$

$0.2\times 0.4 = \_\_\_$

$0.2\times 0.04 = \_\_\_$

$0.2\times 0.004 = \_\_\_$

ii $3\times 5 = 15$

$0.3\times 5 = \_\_\_$

$0.3\times 0.5 = \_\_\_$

$0.3\times 0.05 = \_\_\_$

$0.3\times 0.005 = \_\_\_$

👀 Show answer
i: $0.2\times 4 = 0.8$ $0.2\times 0.4 = 0.08$ $0.2\times 0.04 = 0.008$ $0.2\times 0.004 = 0.0008$

ii: $0.3\times 5 = 1.5$ $0.3\times 0.5 = 0.15$ $0.3\times 0.05 = 0.015$ $0.3\times 0.005 = 0.0015$

17. b) Work out:

i) $0.1\times 0.09$

ii) $0.6\times 0.8$

iii) $0.07\times 0.4$

iv) $0.03\times 0.05$

v) $0.12\times 0.3$

vi) $0.06\times 0.11$

👀 Show answer
i) $0.1\times 0.09 = 0.009$
ii) $0.6\times 0.8 = 0.48$
iii) $0.07\times 0.4 = 0.028$
iv) $0.03\times 0.05 = 0.0015$
v) $0.12\times 0.3 = 0.036$
vi) $0.06\times 0.11 = 0.0066$

18. Fill in the missing spaces in this spider diagram. All the calculations give the answer in the middle ($0.36$). All the answers are in the yellow rectangle on the right.

Spider diagram with 0.36 in the middle and missing numbers

👀 Show answer
$0.6\times 0.6 = 0.36$ ✔
$0.9\times 0.4 = 0.36$ → missing: $0.4$
$36\times 0.01 = 0.36$ → missing: $36$
$3\times 0.12 = 0.36$ → missing: $3$
$0.06\times 6 = 0.36$ → missing: $0.06$
$0.04\times 9 = 0.36$ → missing: $0.04$
$0.3\times 1.2 = 0.36$ → missing: $0.3$
 

🧠 Think like a Mathematician

Given:$42 \times 87 = 3654$

a) Use this information to find the results of:

  1. $42 \times 8.7$
  2. $42 \times 0.87$
  3. $4.2 \times 87$
  4. $4.2 \times 8.7$

b) Explain why your answers to (i) and (iii) are the same, and why your answers to (ii) and (iv) are the same.

c) Generalise a method that can be used to adjust the calculation $42 \times 87 = 3654$ to solve other similar problems with decimals, such as $0.42 \times 0.87$ or $0.042 \times 8.7$.

👀 show answer
  • a)
    • (i) $42 \times 8.7 = 365.4$
    • (ii) $42 \times 0.87 = 36.54$
    • (iii) $4.2 \times 87 = 365.4$
    • (iv) $4.2 \times 8.7 = 36.54$
  • b) In (i) and (iii), one number is 10 times smaller while the other is 10 times larger, so the product stays the same. The same reasoning applies for (ii) and (iv).
  • c) Start from the known product $42 \times 87 = 3654$. - If one factor is divided by 10, divide the product by 10. - If one factor is multiplied by 10, multiply the product by 10. Apply these adjustments according to the decimal shift in each factor.
 

EXERCISES

20. a) Work out $158 \times 46$.

b) Use your answer to part a to write the answers to these multiplications:

i) $15.8 \times 46$

ii) $158 \times 4.6$

iii) $15.8 \times 4.6$

iv) $1.58 \times 4.6$

v) $15.8 \times 0.46$

vi) $1.58 \times 0.046$

👀 Show answer
a) $158 \times 46 = (158 \times 40) (158 \times 6) = 6320 948 = \boxed{7268}$

b) i) $15.8 \times 46 = \dfrac{7268}{10} = \boxed{726.8}$
ii) $158 \times 4.6 = \dfrac{7268}{10} = \boxed{726.8}$
iii) $15.8 \times 4.6 = \dfrac{7268}{100} = \boxed{72.68}$
iv) $1.58 \times 4.6 = \dfrac{7268}{1000} = \boxed{7.268}$
v) $15.8 \times 0.46 = \dfrac{7268}{1000} = \boxed{7.268}$
vi) $1.58 \times 0.046 = \dfrac{7268}{100000} = \boxed{0.07268}$

21. Sam uses this method to work out and check her answer.

Sam's grid method for 0.67 × 4.28 with rounding check

🔎 Reasoning Tip

Estimation check: Use estimation to check your answers by rounding all the numbers in the question to one significant figure.

a) Write the advantages and disadvantages of Sam’s method.

b) Can you improve her method?

c) Which method do you prefer to use to multiply decimals? Write why you prefer this method.

👀 Show answers
a)Advantages: Grid/partial‑products keeps place value clear; systematic; scales to larger numbers. Rounding check gives a sensible estimate. Disadvantages: Many partial products → slower; rounding to $0.7\times 4=2.8$ is a loose check (not very tight); writing $67\times 428$ then placing the decimal at the end would be quicker.

b) Possible improvements: • Compute $67\times 428=28\,676$ then place 4 decimal places → $\boxed{2.8676}$. • Or use compensation: $(0.7-0.03)\times 4.28=2.996-0.1284=\boxed{2.8676}$. • Or split: $0.67\times 4 0.67\times 0.28 = 2.68 0.1876 = \boxed{2.8676}$. • Tighter check: $0.67\times 4.3\approx 2.881$ and $0.67\times 4.2\approx 2.814$ → answer should be between $2.814$ and $2.881$.

c) Sample preference: “Multiply as integers then fix the decimal places.” It’s fast (one main multiplication) and reduces chance of misplacing partial products; I use grid/area only for teaching place value.

22. Work out these multiplications. Show how to check your answers.

a) $6.7 \times 9.4$

b) $0.56 \times 8.3$

c) $0.23 \times 8.15$

d) $0.69 \times 0.254$

👀 Show answers
a) $6.7\times 9.4=\dfrac{67\times 94}{100}=\dfrac{6298}{100}=\boxed{62.98}$. Check: $7\times 9\approx 63$ ✔️

b) $0.56\times 8.3=\dfrac{56\times 83}{1000}=\dfrac{4648}{1000}=\boxed{4.648}$. Check: $0.6\times 8.3\approx 4.98$ (close).

c) $0.23\times 8.15=\dfrac{23\times 815}{10000}=\dfrac{18\,745}{10000}=\boxed{1.8745}$. Check: $0.2\times 8\approx 1.6$; $0.25\times 8\approx 2$ → answer between, as expected.

d) $0.69\times 0.254=\dfrac{69\times 254}{100000}=\dfrac{17\,526}{100000}=\boxed{0.17526}$. Check: $0.7\times 0.25=0.175$ (very close).

23. This is part of Syra’s homework. Use estimation to check if Syra’s answers could be correct. If not, explain why.

Question — Work out
a) 0.45 × 2.8    b) 7.8 × 0.0093    c) 0.065 × 0.043
Syra's answers
a) 12.6    b) 0.07254    c) 0.02795
👀 Show answers
a) Exact $= \dfrac{45\times 28}{1000}=1.26$. Estimate $0.5\times 3 \approx 1.5$. Syra’s $12.6$ is ×10 too big → incorrect.

b) Exact $= \dfrac{78\times 93}{100000}=0.07254$. Reasonable estimate $\approx 8\times0.01=0.08$. Syra is correct.

c) Exact $= \dfrac{65\times 43}{10^6}=0.002795$. Estimate $\approx 0.07\times0.04=0.0028$. Syra’s $0.02795$ is ×10 too big → incorrect.

24. A vet needs to work out how much medicine to give to a cat.

Instruction: Give 7.3 mg (medicine) per kg (mass of cat).

The cat has a mass of 5.8 kg.

a) Estimate the number of milligrams (mg) needed.
b) Calculate the accurate number of milligrams (mg) needed.

👀 Show answers
a) Estimate: $7\times 6 \approx \boxed{42\ \text{mg}}$.

b) Accurate: $7.3\times 5.8=\dfrac{73\times 58}{100}=\boxed{42.34\ \text{mg}}$.

25. A coin is made from silver and copper. The mass of the coin is 4.2 g.

Formula: mass of silver = 0.775 × mass of coin

a) Estimate the mass of the silver in this coin.
b) Calculate the accurate mass of the silver in this coin.

👀 Show answers
a) Estimate: $0.8 \times 4 \approx \boxed{3.2\ \text{g}}$ (any close sensible estimate OK).

b) Accurate: $0.775\times 4.2=\boxed{3.255\ \text{g}}$.
 

⚠️ Be careful!

When multiplying decimals, never place the decimal point by eye — always count the total number of decimal places in the question and make sure the answer has the same total. For example, $3.2 \times 0.04$ has three decimal places in total, so the product must be $0.128$, not $1.28$.

 

📘 What we've learned — Multiply Decimals by Whole Numbers & Decimals

  • Ignore decimals at first: multiply the numbers as if they were whole numbers, then place the decimal back in the product.
  • Decimal placement rule: total decimal places in the product = sum of decimal places in all factors.
    Example: $0.002\times4$ → $2\times4=8$ → 3 d.p. → $0.008$.
  • Using powers of ten: rewrite decimals in terms of $10^n$ to simplify multiplication mentally.
    Example: $30\times0.06 = (3\times10)\times(6\times10^{-2}) = 18\times10^{-1} = 1.8$.
  • Round and adjust: round a factor to a nearby easy number, multiply, then adjust for the difference.
    Example: $476\times3.7 \approx 476\times4 = 1904$, then subtract $0.3\times476=142.8$ → $1761.2$.
  • Written method: perform long multiplication without decimals, then insert the decimal point according to total decimal places.
    Example: $476\times3.7$ → calculate $476\times37$ → insert 1 d.p. → $1761.2$.
  • Sign rules:
    • Positive × Positive = Positive
    • Positive × Negative = Negative
    • Negative × Negative = Positive
  • Estimation check: round each factor to 1 s.f. and multiply to see if your answer is reasonable.
  • Size sense-check:
    • Both factors < 1 → product smaller than each factor
    • One factor < 1 → product smaller than the larger factor
    • Factor = 0 → product is 0
  • Common mistakes to avoid:
    • Miscounting decimal places when placing the decimal point
    • Forgetting to adjust after rounding
    • Incorrect sign when multiplying with negatives