Sometimes numbers are written in words. You need to read and understand numbers and number words.
Exercise $1.9$
$1$. Write each of the numbers represented in words.
a.
b.
c. $93$
d. $31$

a. $84$ is eighty-four.
b. $57$ is fifty-seven.
c. $93$ is ninety-three.
d. $31$ is thirty-one.
$2$. Read the number words and write the number.
a. forty-two
b. seventy-six
c. twenty-five
d. sixty-eight
a. forty-two = $42$
b. seventy-six = $76$
c. twenty-five = $25$
d. sixty-eight = $68$
$3$. Use these number words to write some $2$-digit numbers in words. How many different numbers can you write?
twenty seventy forty eight nine
You can make these $2$-digit numbers:
twenty ($20$), forty ($40$), seventy ($70$), twenty-eight ($28$), twenty-nine ($29$), forty-eight ($48$), forty-nine ($49$), seventy-eight ($78$), seventy-nine ($79$).
That is $9$ different numbers.
Investigation: Marcus says there is only one 2-digit number word with 12 letters, seventy-seven. Is Marcus correct?
Equipment: Paper and pen (optional: a list of the number words from 10 to 99)
Method:
Follow-up Questions:
$4$. Round each number to the nearest $10$. Use the number line to help you.
a. $64$
b. $72$
c. $81$
d. $56$
e. $49$
f. $23$
g. $27$
h. $35$
i. $30$
a.$64$ rounds to $60$.
b.$72$ rounds to $70$.
c.$81$ rounds to $80$.
d.$56$ rounds to $60$.
e.$49$ rounds to $50$.
f.$23$ rounds to $20$.
g.$27$ rounds to $30$.
h.$35$ rounds to $40$.
i.$30$ rounds to $30$.
$5$. A number rounded to the nearest $10$ is $60$.
What could the number be?
Any number from $55$ to $64$ rounds to $60$ (to the nearest $10$).
For example: $58$, $60$, or $63$.
$6$. Find $4$ different ways to regroup $31$. Draw or write your answers.
Compare the ways you regrouped $31$ with a partner.
What did you do the same? What did you do differently?

Four regroupings of $31$:
$31 = 3$ tens $+ 1$ one.
$31 = 2$ tens $+ 11$ ones.
$31 = 1$ ten $+ 21$ ones.
$31 = 0$ tens $+ 31$ ones.
Compare: You might both have used tens and ones, but you may have traded different numbers of tens for ones (for example, one person might write $2$ tens and $11$ ones, while another writes $1$ ten and $21$ ones).
Investigation: Is Arun correct? If he is correct, will Arun’s method always tell you how many different ways there are to regroup a number?

Arun says:$21$ is $2$ tens and $1$ one. $2 + 1 = 3$ so there will only be $3$ ways to regroup $21$ using tens and ones.
Method:
Follow-up Questions:
1. The regroupings of $21$ using tens and ones are:
2. There are $3$ different ways.
3.Yes, Arun is correct for $21$. The number really is $3$.
4.No, Arun’s method does not always work. For any number that is written as $T$ tens and $O$ ones, you can regroup by trading tens for ones, which gives exactly $T + 1$ different tens-and-ones forms (from $T$ tens down to $0$ tens). So the number of ways depends on the number of tens, not on $T + O$. For example, $31$ is $3$ tens and $1$ one: Arun’s method would give $3 + 1 = 4$, but the true number of regroupings is $3 + 1 = 4$ ways because there are $3$ tens (not because $3 + 1$). If the ones digit changes, the number of regroupings stays the same as long as the tens digit stays the same.