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Counting & sequences

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visibility 25update 6 days agobookmarkshare

🎯 In this topic you will

  • Count forwards and backwards using fractions and decimals.
  • Find and use the position-to-term rule of a sequence.
 

🧠 Key Words

  • position
  • position-to-term rule
  • term
  • term-to-term rule
Show Definitions
  • position: The place number of a term in a sequence, such as 1st, 2nd, or 10th.
  • position-to-term rule: A rule or formula that gives the value of any term directly from its position number in the sequence.
  • term: One number or item in a sequence.
  • term-to-term rule: A rule that tells you how to get from one term to the next term in a sequence.
 

🔢 From Term-to-Term to Position-to-Term

In Stage 5, you learnt how to use a term-to-term rule to find the next term in a sequence. In this unit, you will learn how to use the position-to-term rule to find any term in a sequence.

 

 

How to Work it Out:   The 25th term is $25 \times 4 = 100$

 
📘 Worked example

a. Follow the instructions in the flow diagram to generate a sequence.

b. What is the position-to-term rule for the sequence?

c. Imagine the sequence continues forever.
What is the 50th term in the sequence?

Answer:

a. $2, 4, 6, 8, 10, 12, 14, 16, 18, 20$

b. Make a table to show the position and the term.

Position Term
1 2
2 4
3 6

The position-to-term rule is: multiply by 2

c. $50 \times 2 = 100$

Follow the flow diagram: start at $2$, then keep adding $2$ each time and write down each answer.

We include $20$ because the rule says stop only when the answer is more than $20$, and $20$ is not more than $20$.

Compare the position number with the term number: $1 \to 2$, $2 \to 4$, $3 \to 6$. Each term is double its position, so the position-to-term rule is multiply by $2$ (that is, $2n$).

To find the 50th term, use the position-to-term rule directly: $50 \times 2 = 100$.

 

EXERCISES

$1$.

a. Find the position-to-term rule for the numbers in this table.

Position Term
$1$ $6$
$2$ $12$
$3$ $18$
$4$ $24$

b. What is the $10$th term of the sequence $6, 12, 18 \ldots$?

👀 Show answer

a. The position-to-term rule is multiply by $6$, so the term is $6n$.

b. The $10$th term is $10 \times 6 = 60$.

$2$. The numbers in this sequence increase by equal amounts each time.

a. Write the three missing numbers.

$3, \square, \square, \square, 15$

b. What is the term-to-term rule for the sequence?

c. What is the position-to-term rule for the sequence?

👀 Show answer

a. The missing numbers are $6, 9, 12$.

b. The term-to-term rule is add $3$.

c. The position-to-term rule is multiply by $3$, so the term is $3n$.

$3$.

a. Follow the instructions in the flow diagram to generate a sequence.

 

b. What is the position-to-term rule for the sequence?

c. Imagine the sequence continues forever.
What is the $50$th term in the sequence?

👀 Show answer

a. The sequence is $8, 16, 24, 32, 40, 48$.

We stop before writing $56$ because $56$ is more than $50$.

b. The position-to-term rule is multiply by $8$, so the term is $8n$.

c. The $50$th term is $50 \times 8 = 400$.

$4$. Here is the start of a sequence using rectangles and triangles. Each rectangle is numbered.

 

The sequence continues in the same way.

a. How many triangles are there in the shape with $50$ rectangles?
How many rectangles and triangles are there altogether in that shape?

b. Jodi starts to make a table showing the position (shape number) and the term (total number of rectangles and triangles). Copy and complete her table.

Position Term
$1$ $3$
$2$  
$3$ $9$
$4$ $12$
$5$  

c. What is the position-to-term rule for Jodi's sequence?

d. What is the $50$th term in the sequence?

👀 Show answer

a. With $50$ rectangles, there are $100$ triangles (two triangles for each rectangle).

Altogether there are $50 + 100 = 150$ shapes.

b. Completed table terms: position $2 \to 6$ and position $5 \to 15$.

c. The position-to-term rule is multiply by $3$, so the term is $3n$.

d. The $50$th term is $50 \times 3 = 150$.

$5$. Pablo counts up in quarters.

What are the two missing numbers?

$\frac{1}{4}, \frac{1}{2}, \frac{3}{4}, 1, \square, 1\frac{1}{2}, \square, 2$

👀 Show answer
The missing numbers are $1\frac{1}{4}$ and $1\frac{3}{4}$.

$6$.

a. Write a sequence with steps of constant size in which the first term is $1$ and the fifth term is $1.04$.

$\square, \square, \square, \square, \square$

b. What is the $10$th term?

👀 Show answer

a. One correct sequence is $1, 1.01, 1.02, 1.03, 1.04$.

b. The $10$th term is $1.09$.

$7$. Ollie writes a number sequence starting at $15$ and counting back in steps of $0.4$.

$15, 14.6, 14.2, 13.8, \ldots$

He says, '$1.5$ cannot be in my sequence.'

Ollie is correct. How do you know without counting back?

Discuss your answer with your partner.

👀 Show answer
A term would have to be $15 - 0.4k$ for a whole number $k$. If $15 - 0.4k = 1.5$, then $0.4k = 13.5$, so $k = 33.75$, which is not a whole number. Therefore $1.5$ is not in the sequence.

$8$. Hassan counts back in steps of $\frac{2}{5}$ starting at $0$.

He counts $0, -\frac{2}{5}, -\frac{4}{5}, -1\frac{1}{5}, \ldots$

Which of these numbers could Hassan say?

$-1\frac{4}{5} \qquad -2 \qquad -3 \qquad -3\frac{3}{5} \qquad -4$

👀 Show answer
Hassan can say numbers that are multiples of $\frac{2}{5}$ below $0$. From the list, the possible numbers are $-2$, $-3\frac{3}{5}$, and $-4$.

$9$. Samira counts on from $20$ in steps of $1.001$

$20 \qquad 21.001 \qquad 22.002 \qquad 23.003 \qquad \ldots$

Write the first number Samira says which is bigger than $30$.

👀 Show answer
The first number bigger than $30$ is $30.01$ (after $10$ steps: $20 + 10 \times 1.001 = 30.01$).
 

🧠 Think like a Mathematician

The diagram shows the first five hexagonal numbers: $1, 6, 15, 28, 45, \ldots$

 

Tasks:

  1. How does the sequence continue?
  2. What is the next number in the sequence?
  3. Write these numbers as the sum of two hexagonal numbers: $12, 21, 39, 30$.
  4. The first one is done for you: $12 = 6 + 6$.
  5. Investigate which other numbers, less than $100$, can be written as the sum of two hexagonal numbers.
👀 show answer

Sequence pattern: The differences are $+5, +9, +13, +17$, so they increase by $4$ each time. The next difference is $+21$.

Next hexagonal number:$45 + 21 = 66$.

Writing the given numbers as sums of two hexagonal numbers:

  • $12 = 6 + 6$ (given)
  • $21 = 15 + 6$
  • $39 = 28 + 6$
  • $30 = 15 + 15$

Hexagonal numbers less than 100:$1, 6, 15, 28, 45, 66, 91$

Other numbers less than 100 that can be written as the sum of two hexagonal numbers (in addition to $12, 21, 30, 39$):

$2, 7, 16, 22, 29, 34, 43, 46, 51, 57, 60, 67, 72, 73, 77, 79, 87, 90, 92, 94, 97$

 

✅ Look what I can do!

  • I can count on and back using fractions and decimals.
  • I can find and use the position-to-term rule in a sequence.

Related Past Papers

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