Intersecting lines
🎯 In this topic you will
- Recognise the properties of angles on perpendicular lines and intersecting lines
- Recognise the properties of angles on parallel lines
🧠 Key Words
- intersect
- opposite angles
- perpendicular
- parallel
- transversal
Show Definitions
- intersect: To cross or meet at a point, such that the lines share a common point.
- opposite angles: Angles formed opposite each other when two lines intersect, which are always equal in measure.
- perpendicular: Lines that meet at a right angle (90°).
- parallel: Lines that are always the same distance apart and never meet, no matter how far they are extended.
- transversal: A line that cuts across two or more other lines at different points.
➗ Intersecting Lines
These two lines intersect at $A$.

When two lines intersect, opposite angles are equal.

In this diagram, $a$ and $c$ are opposite angles. Angles $a$ and $c$ are equal. Also $b$ and $d$ are opposite angles. Angles $b$ and $d$ are equal.
You can use your algebra skills to find unknown angles, represented by letters.
➗ Perpendicular & Parallel Lines with a Transversal
These two lines intersect, as shown. The angle between the two lines is a right angle. They are perpendicular lines.

$AB$ and $CD$ are two lines that do not intersect. They are parallel.
The arrows show that the lines are parallel. The line $EF$ crosses the parallel lines. This line is called a transversal.

In the previous diagram there are only two different sizes of angle. The four angles at the top are the same as the four angles at the bottom.
$70^\circ 110^\circ = 180^\circ$
$70^\circ 110^\circ 70^\circ 110^\circ = 360^\circ$

❓ EXERCISES
1. Work out the angles that have a letter.
a.

b.

👀 Show answer
a. On a straight line: $x = 180^\circ - 53^\circ = 127^\circ$. Opposite angles are equal: $y = 53^\circ$.
b. On a straight line: $w = 180^\circ - 114^\circ = 66^\circ$. Opposite angles are equal: $z = 114^\circ$.
2. Two straight lines are shown.
There are four angles. One of the angles is $87^\circ$.
Work out the other three angles.

👀 Show answer
Opposite angles are equal, so the angle opposite $87^\circ$ is also $87^\circ$. Adjacent angles on a straight line sum to $180^\circ$, so the other two angles are each $180^\circ - 87^\circ = 93^\circ$.
❓ EXERCISES
3. Three straight lines meet at a point.
Calculate the values of $a$, $b$, $c$ and $d$. Give reasons for your answers.

👀 Show answer
Angles on a straight line add to $180^\circ$.
$a = 180^\circ - (61^\circ 46^\circ) = 73^\circ$.
$c = 180^\circ - a = 107^\circ$.
Opposite angles are equal: $b = 61^\circ$, $d = 46^\circ$.
4. There are two parallel lines in this diagram. One angle is $42^\circ$.
Copy the diagram and write in the size of all the other angles.

👀 Show answer
Corresponding angles are equal, so the matching angle is $42^\circ$.
Adjacent angles on a straight line add to $180^\circ$, so the supplementary angles are $180^\circ - 42^\circ = 138^\circ$.
5. Work out the unknown angles $a$, $b$ and $c$.

👀 Show answer
$a = 113^\circ$ (vertically opposite angles).
$b = 180^\circ - a = 67^\circ$ (angles on a straight line).
$c = b = 67^\circ$ (vertically opposite angles).
6. Lines $WX$ and $YZ$ are parallel.
One angle is $77^\circ$. Find $a$, $b$ and $c$.

👀 Show answer
$a = 77^\circ$ (corresponding angles).
$b = 180^\circ - a = 103^\circ$ (angles on a straight line).
$c = b = 103^\circ$ (vertically opposite angles).
❓ EXERCISES
7. $AB$ and $CD$ are parallel lines. Calculate $s$ and $t$.

👀 Show answer
Corresponding angles are equal: $t = 75^\circ$.
Angles on a straight line: $s = 180^\circ - 75^\circ = 105^\circ$.
8. Look at the diagram.
a. Explain why these two lines cannot be parallel.
b. Give your answer to part a to a partner to read. Can your answer be improved?

👀 Show answer
If lines were parallel, corresponding angles would be equal, but $56^\circ \neq 126^\circ$.
9. This shape is made from eight identical triangles.
a. Sketch the diagram and label the other angles equal to $a$, $b$ or $c$.
b. Use arrows to mark any parallel lines.

👀 Show answer
Angles equal to $a$, $b$, $c$ can be found by symmetry of the identical triangles. Mark parallel lines using arrow notation.
10. The diagram shows angle $X$ is $45^\circ$.
a. Calculate $a$.
b. Angle $X$ is increased to $90^\circ$. Find the new value of $a$.
c. Angle $X$ is increased to $119^\circ$. Find the new value of $a$.
d. Can angle $X$ be more than $119^\circ$? Give a reason for your answer.

👀 Show answer
a. $a = 180^\circ - (45^\circ 60^\circ) = 75^\circ$.
b. $a = 180^\circ - (90^\circ 60^\circ) = 30^\circ$.
c. $a = 180^\circ - (119^\circ 60^\circ) = 1^\circ$.
d. No, because the sum of angles in a triangle is $180^\circ$, so $a$ would be negative if $X > 119^\circ$.
11. This trapezium has a pair of parallel sides. Use this fact to calculate the missing angles.

👀 Show answer
Angles on the same side of a transversal add to $180^\circ$.
Angle $D = 180^\circ - 45^\circ = 135^\circ$.
Angle $B = 180^\circ - 67^\circ = 113^\circ$.
🧠 Think like a Mathematician
12. These shapes are an equilateral triangle, a rhombus and a square.

All the sides are the same length. Two squares and three triangles can be placed around a point, as shown.

- a. How do you know that the shapes fit exactly around a point?
- b. Find a different way to fit two squares and three triangles around a point.
- c. Show how to fit only triangles around a point.
- d. Find all the possible ways of fitting only rhombuses around a point.
👀 Show answer
- a. Angles around a point sum to $360^\circ$. Two squares and three equilateral triangles give $2\times90^\circ 3\times60^\circ = 180^\circ 180^\circ = 360^\circ$, so they fit exactly.
- b. Any order that still uses two square corners ($90^\circ$ each) and three triangle corners ($60^\circ$ each) works. Example: T–S–T–S–T around the point (T = triangle corner, S = square corner).
- c. Use six equilateral triangle corners: $6\times60^\circ = 360^\circ$. Arrange $6$ triangles meeting at the point.
- d. A rhombus has angles $60^\circ$ and $120^\circ$. Let $x$ be the number of $60^\circ$ corners at the point and $y$ the number of $120^\circ$ corners. Then $60x 120y=360$ ⇒ $x 2y=6$. Possible fittings (numbers of rhombuses meeting at the point) are:
$\bullet$$6$ rhombuses using $6$ acute corners ($x=6,y=0$)
$\bullet$$5$ rhombuses: $4$ acute $1$ obtuse ($x=4,y=1$)
$\bullet$$4$ rhombuses: $2$ acute $2$ obtuse ($x=2,y=2$)
$\bullet$$3$ rhombuses using $3$ obtuse corners ($x=0,y=3$)

