Do you enjoy eating chocolate? This bar could be split into $24$ pieces or into $6$ lots of $4$ or $4$ lots of $6$.

In this unit, you will multiply larger numbers by $1$-digit numbers. You should always estimate the size of the answer first to check your answer is about right.
1. Magda calculates $14 \times 5$ using factors. She spills ink on her work. What number is under the ink blots?

Since $14 = 7 \times 2$, the missing number is $2$.
So $14 \times 5 = 7 \times 2 \times 5 = 7 \times 10 = 70$, and both ink blots cover $2$.
2. Amir and Ben work out $4 \times 15$.

Which method do you like best? Explain why.
Discuss your answer with your partner.
Think of other ways to work out $4 \times 15$.
Both methods are correct and give $60$.
Amir's method: $4 \times 15 = 4 \times 5 \times 3 = 20 \times 3 = 60$.
Ben's method: $4 \times 15 = 2 \times 2 \times 15 = 2 \times 30 = 60$.
Example preference: Ben's method can feel efficient because doubling $15$ to get $30$ is quick, then doubling again gives $60$.
3. Work out the following. Estimate your answer first.
a. $47 \times 5$
b. $29 \times 4$
c. $89 \times 3$
d. $74 \times 6$
Compare the methods you used with your partner.
Identify the advantages and disadvantages of each method.
a. Estimate: $50 \times 5 = 250$. Exact: $47 \times 5 = 235$.
b. Estimate: $30 \times 4 = 120$. Exact: $29 \times 4 = 116$.
c. Estimate: $90 \times 3 = 270$. Exact: $89 \times 3 = 267$.
d. Estimate: $70 \times 6 = 420$ (or $75 \times 6 = 450$). Exact: $74 \times 6 = 444$.
4. Sultan uses the grid method to work out his calculations, but he spills ink on his work.
Copy and complete the calculations.
a. $47 \times 3 =$
b. $93 \times 4 =$
c. $51 \times 5 =$
d. $87 \times 4 =$

a. $47 \times 3 = (40 \times 3) + (7 \times 3) = 120 + 21 = 141$. Missing number: $120$.
b. $93 \times 4 = (90 \times 4) + (3 \times 4) = 360 + 12 = 372$. Missing numbers: $90$ and $360$.
c. $51 \times 5 = (50 \times 5) + (1 \times 5) = 250 + 5 = 255$. Missing number: $250$.
d. $87 \times 4 = (80 \times 4) + (7 \times 4) = 320 + 28 = 348$. Missing numbers: $7$ and $320$.
5. Find the product of $56$ and $5$.
$56 \times 5 = 280$.
6. Pencils are sold in packs of $5$. Each pack costs $95$ cents. Fatima buys $4$ packs of pencils. How much does she spend?
$4 \times 95 = 380$, so she spends $380$ cents (that is $3.80$).
7. Use the digits $2$, $3$ and $5$ once to make the multiplication with the greatest product.

Work out the answer.
Compare your answer with your partner.
The person with the larger answer should explain their method.
To make the product as large as possible, use the largest digit as the multiplier and make the largest possible two-digit number with the other two digits.
$32 \times 5 = 160$.
8. Work out the following. Estimate your answer first.
a. $174 \times 4$
b. $129 \times 7$
c. $189 \times 3$
d. $119 \times 8$
Compare the methods you used with your partner.
Identify the advantages and disadvantages of each method.
a. Estimate: $170 \times 4 = 680$ (or $175 \times 4 = 700$). Exact: $174 \times 4 = 696$.
b. Estimate: $130 \times 7 = 910$. Exact: $129 \times 7 = 903$.
c. Estimate: $190 \times 3 = 570$. Exact: $189 \times 3 = 567$.
d. Estimate: $120 \times 8 = 960$. Exact: $119 \times 8 = 952$.
A 3-digit number is multiplied by 3. There are five different missing digits in the calculation: 1, 2, 6, 7, 8.
Calculation (with blanks):
Clues:
Follow-up Questions:
First, the digits are consecutive and sum to 24. So they must be 7, 8, 9 because $7+8+9=24$.
The middle digit shown is 9, so the number is either 897 or 798 (not in order, so 789 is not allowed).
Now multiply by 3 and use the “missing digits are 1, 2, 6, 7, 8” condition:
Therefore, the completed calculation is: 897 × 3 = 2691 (and 2691 is between 2000 and 3000).