In this section you will investigate numbers written as powers.
Look at these powers of 5:
| n | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| 5n | 1 | 5 | 25 | 125 | 625 | 3125 |
So 53 = 5 × 5 × 5 = 125 and 54 = 5 × 5 × 5 × 5 = 625 and so on.
As you move to the right the numbers in the bottom row multiply by 5.
As you move to the left the numbers in the bottom row divide by 5.
3125 ÷ 5 = 625, 625 ÷ 5 = 125, 125 ÷ 5 = 25
If you continue to divide by 5, 25 ÷ 5 = 5 so 51 = 5
There is another number missing in the table. What is 50?
Divide by 5 again: 50 = 51 ÷ 5 = 5 ÷ 5 = 1
So 50 = 1
If n is any positive integer then n0 = 1.
1. Copy and complete this list of powers of 2.
| Power | $2^0$ | $2^1$ | $2^2$ | $2^3$ | $2^4$ | $2^5$ | $2^6$ | $2^7$ | $2^8$ | $2^9$ | $2^{10}$ |
|---|---|---|---|---|---|---|---|---|---|---|---|
| Number | 1 | 2 | 8 | 64 | 512 |
2. Copy and complete this list of powers of 3.
| Power | $3^0$ | $3^1$ | $3^2$ | $3^3$ | $3^4$ | $3^5$ | $3^6$ | $3^7$ | $3^8$ |
|---|---|---|---|---|---|---|---|---|---|
| Number | 3 | 27 | 2187 |
Question: What happens when you multiply numbers written as powers of 2 or powers of 3?
Equipment: Calculator (optional), pencil, paper
Look at this multiplication: $4 \times 16 = 64$
You can write all the numbers as powers of 2: $2^2 \times 2^4 = 2^6$
Generalising: Generalising means using a set of results to come up with a general rule.
Follow-up Questions:
3. Write the answers to these calculations as powers of 6:
a) $6^2 \times 6^3$
b) $6^4 \times 6$
c) $6^5 \times 6^2$
d) $6^3 \times 6^3$
4. Write the answers to these calculations in index form:
a) $10^3 \times 10^2$
b) $20^5 \times 20$
c) $15^3 \times 15^3$
d) $5^5 \times 5^3$
5. a) $3^8 = 6561$. Use this fact to find $3^9$ and show your method.
b) $5^6 = 15\,625$. Use this fact to find $5^7$ and show your method.
6. Find the missing power:
a) $3^3 \times 3^{\square} = 3^5$
b) $9^3 \times 9^{\square} = 9^8$
c) $12^4 \times 12^{\square} = 12^6$
d) $15^{\square} \times 15^3 = 15^{10}$
7. Read what Sofia says:
$4^2$ is equal to $2^4$ and $4^3$ is equal to $3^4$
Is Sofia correct? Give a reason for your answer.
8. A million is $10^6$. A billion is 1000 million.
Write as a power of 10:
a) one billion
b) 1000 billion
9. Write in index form:
a) $2^2 \times 2^3 \times 2$
b) $3^3 \times 3^4 \times 3^2$
c) $5 \times 5^3 \times 5^3$
d) $10^3 \times 10^2 \times 10^4$
10. a) $(3^2)^3 = 3^2 \times 3^2 \times 3^2$. Write $(3^2)^3$ as a single power of 3.
b) Write in index form:
i) $(2^3)^2$
ii) $(5^3)^2$
iii) $(4^2)^3$
iv) $(15^2)^4$
v) $(10^4)^3$
c) $N$ is a positive integer. Write in index form:
i) $(N^2)^3$
ii) $(N^4)^2$
iii) $(N^5)^3$
d) Can you generalise the results of part c?
Question: How can divisions be written using indices (powers)? What patterns can you discover?
Equipment: Pencil, paper, calculator (optional)
Here is a division: $32 \div 4 = 8$
You can write this using indices: $2^5 \div 2^2 = 2^3$
Follow-up Questions:
11. Write the answers to these calculations in index form:
a) $2^7 \div 2^5$
b) $10^6 \div 10^3$
c) $15^8 \div 15^6$
d) $8^{10} \div 8^9$
e) $2^{15} \div 2^{11}$
f) $2^5 \div 2^5$
12. Write the answers to these calculations in index form:
a) $9^5 \times 9^2$
b) $9^5 \div 9^2$
c) $(9^5)^2$
d) $5^5 \times 5^4$
e) $12^8 \div 12^3$
f) $(7^3)^3$
g) $(10^1)^4$
13. Read what Zara says:
"I think that $(5^2)^3 = (5^3)^2$"
a) Is Zara correct? Give a reason for your answer.
b) Is a similar result true for other indices?
14. $15 = 3 \times 5$
Use this fact to write as a product of prime factors:
a) $15^2$
b) $15^3$
c) $15^5$
d) $15^8$
15. a) Write $5^6 \div 5^4$ as a power of 5.
b) Write $5^6 \div 5^6$ as a power of 5.
c) Is it possible to write $5^4 \div 5^6$ as a power of 5?
Now that you’ve mastered powers with positive integers — including how to multiply and divide them using index laws — you're ready to extend these ideas to zero and negative powers. You'll discover why \(a^0 = 1\), what negative indices mean, and how they fit perfectly into the same patterns you've already seen.
This table shows powers of 3.
| 32 | 33 | 34 | 35 | 36 |
| 9 | 27 | 81 | 243 | 729 |
Index notation: The index is the small red number written above and to the right of the base.
When you move one column to the right, the index increases by 1 and the number multiplies by 3.
9 × 3 = 27 27 × 3 = 81 81 × 3 = 243, and so on.
When you move one column to the left, the index decreases by 1 and the number divides by 3. You can use this fact to extend the table to the left:
| 3–4 | 3–3 | 3–2 | 3–1 | 30 | 31 | 32 | 33 | 34 | 35 | 36 |
|---|---|---|---|---|---|---|---|---|---|---|
| 1⁄81 | 1⁄27 | 1⁄9 | 1⁄3 | 1 | 3 | 9 | 27 | 81 | 243 | 729 |
Power of zero: \( 3^0 = 1 \) may seem unusual, but it follows the pattern of dividing by 3 each time the power decreases.
9 ÷ 3 = 3 3 ÷ 3 = 1 1 ÷ 3 = $\dfrac{1}{3}$ $\dfrac{1}{3}$ ÷ 3 = $\dfrac{1}{9}$ $\dfrac{1}{9}$ ÷ 3 = $\dfrac{1}{27}$, and so on.
You can see from the table that 31 = 3 and 30 = 1.
Also: 3–1 = $\dfrac{1}{3}$ 3–2 = $\dfrac{1}{3^2}$ 3–3 = $\dfrac{1}{3^3}$, and so on.
In general, if n is a positive integer then 3–n = $\dfrac{1}{3^n}$. These results are not only true for powers of 3. They apply to any positive integer.
For example: 5–2 = $\dfrac{1}{5^2}$ = $\dfrac{1}{25}$ 8–3 = $\dfrac{1}{8^3}$ = $\dfrac{1}{512}$ 60 = 1
In general, if a and n are positive integers then a0 = 1 and a–n = $\dfrac{1}{a^n}$.
16. Write each number as a fraction:
a) $4^{-1}$
b) $2^{-3}$
c) $9^{-2}$
d) $6^{-3}$
e) $10^{-4}$
f) $2^{-5}$
17. Here are five numbers:
$2^{-4},\quad 3^{-3},\quad 4^{-2},\quad 5^{-1},\quad 6^0$
List the numbers in order of size, smallest first.
18. Write these numbers as powers of 2:
a) $\dfrac{1}{2}$
b) $\dfrac{1}{4}$
c) $64$
d) $\dfrac{1}{64}$
e) $1$
f) $8^{-1}$
19. Write each number as a power of 10:
a) $100$
b) $1000$
c) $1$
d) $0.1$
e) $0.001$
f) $0.000001$
20. Write $\dfrac{1}{64}$
a) as a power of 64
b) as a power of 8
c) as a power of 4
d) as a power of 2
21. a) Write $\dfrac{1}{81}$ as a power of a positive integer.
b) How many different ways can you write the answer to part a?
22. When $x = 6$, find the value of:
a) $x^2$
b) $x^{-2}$
c) $x^0$
d) $x^{-3}$
23. Write $m^{-2}$ as a fraction when:
a) $m = 9$
b) $m = 15$
c) $m = 1$
d) $m = 20$
24. $y = x^2 + x^{-2}$ and $x$ is a positive number.
a) Write $y$ as a mixed number when:
i) $x = 1$ ii) $x = 2$ iii) $x = 3$
b) Find the value of $x$ when:
i) $y = 25.04$ ii) $y = 100.01$
25. a) Write the answer to each multiplication as a power of 3:
i) $3^2 \times 3^3$
ii) $3^4 \times 3^5$
iii) $3^6 \times 3^4$
iv) $3 \times 3^5$
b) In part a you used the rule $3^a \times 3^b = 3^{a+b}$ when the indices are positive integers.
In the following multiplications, $a$ or $b$ can be negative integers.
Show that the rule still gives the correct answers:
i) $3^2 \times 3^{-1}$
ii) $3^{-2} \times 3$
iii) $3^3 \times 3^{-1}$
iv) $3^{-1} \times 3^{-1}$
v) $3^{-2} \times 3^{-1}$
c) Write two examples of your own to show that the rule works.
26. Write the answer to each multiplication as a power of 5:
a) $5^4 \times 5^2$
b) $5^4 \times 5^{-2}$
c) $5^{-4} \times 5^2$
d) $5^{-4} \times 5^{-2}$
12. Write the answer to each multiplication as a single power:
a) $6^{-3} \times 6^2$
b) $7^5 \times 7^{-2}$
c) $11^{-4} \times 11^{-6}$
d) $4^{-6} \times 4^2$
27. Find the value of $x$ in each case:
a) $2^5 \times 2^x = 2^9$
b) $3^x \times 3^{-2} = 3^4$
c) $4^x \times 4^{-3} = 4^{-5}$
d) $12^{-3} \times 12^x = 12^2$
Question: How do you simplify divisions of powers using index laws? Does the same rule work for negative indices?
Equipment: Pencil, paper, calculator (optional)
Method:
Follow-up Questions:
28. Write the answer to each division as a single power:
a) $6^2 \div 6^5$
b) $9^3 \div 9^4$
c) $15^2 \div 15^6$
d) $10^3 \div 10^8$
29. Write the answer to each division as a single power:
a) $2^2 \div 2^{-3}$
b) $8^5 \div 8^{-2}$
c) $5^{-4} \div 5^2$
d) $12^{-3} \div 12^{-5}$
30. Write down:
a) $8^3$ as a power of 2
b) $8^{-3}$ as a power of 2
c) $27^2$ as a power of 3
d) $27^{-2}$ as a power of 3
e) $27^2$ as a power of 9
f) $27^{-2}$ as a power of 9
Don’t confuse negative indices with negative numbers. A negative index like $2^{-3}$ means $\dfrac{1}{2^3}$, not $-2^3$. It’s about reciprocals, not negatives!