You can write all the numbers $10$, $100$, $1000$, $10000$, … as powers of 10. The power of $10$ is written as an index. This is the number of 10s that you multiply together to get the final number. It is also the same as the number of zeros that follow the digit 1.
Look at this pattern of numbers:
$10 = 10^1$ 10 is ten to the power of 1 or simply 10.
$100 = 10 \times 10 = 10^2$ 100 is ten to the power of 2 or ‘10 squared’.
$1000 = 10 \times 10 \times 10 = 10^3$ 1000 is ten to the power of 3 or ‘10 cubed’.
$10000 = 10 \times 10 \times 10 \times 10 = 10^4$ 10000 is ten to the power of 4.
Pattern growth: As this pattern continues, the numbers get larger and larger.
When you multiply a number by a power of $10$, you move the digits in the number to the left in the place value table.
When you divide a number by a power of $10$, you move the digits in the number to the right in the place value table.
1. Write the following in:
i numbers ii words
a. $10^{3}$
b. $10^{5}$
c. $10^{7}$
d. $10^{1}$
i numbers
a. $1\,000$ b. $100\,000$ c. $10\,000\,000$ d. $10$
ii words
a. one thousand b. one hundred thousand c. ten million d. ten
2. Write each number as a power of $10$.
a. $100$
b. $100\,000\,000$
c. $10\,000$
d. $10\,000\,000\,000$
a. $10^{2}$ b. $10^{8}$ c. $10^{4}$ d. $10^{10}$
3. Copy and complete the working for each of these.
a. $3 \times 10^{4} = 3 \times 10\,000 = \square$
b. $5 \times 10^{6} = 5 \times 1\,000\,000 = \square$
c. $45 \times 10^{5} = 45 \times 100\,000 = \square$
d. $291 \times 10^{3} = 291 \times 1000 = \square$
a. $30\,000$ b. $5\,000\,000$ c. $4\,500\,000$ d. $291\,000$
4. Marcus says: ‘When I multiply a whole number by $10^{4}$, I just have to add four zeros to the end of the number. When I multiply a whole number by $10^{5}$, I just have to add five zeros to the end of the number. This works for any positive whole number power.’
Is Marcus correct? Discuss in pairs or groups.
Yes, for whole numbers. Multiplying a whole number by $10^{n}$ shifts its digits $n$ places to the left, which is the same as appending $n$ zeros (e.g., $37 \times 10^{4} = 370\,000$). This rule is specific to whole numbers in base $10$; numbers with decimals require shifting the decimal point instead of just adding zeros.
5. Work out:
a. $23 \times 10^{2}$
b. $768 \times 10^{4}$
c. $9 \times 10^{6}$
a. $2\,300$ b. $7\,680\,000$ c. $9\,000\,000$
6. Copy and complete the working for each of these.
a. $4.2 \times 10^{2} = 4.2 \times 100 = \square$
b. $6.5 \times 10^{4} = 6.5 \times 10\,000 = \square$
c. $12.7 \times 10^{3} = 12.7 \times 1000 = \square$
d. $2.87 \times 10^{6} = 2.87 \times 1\,000\,000 = \square$
a. $420$ b. $65\,000$ c. $12\,700$ d. $2\,870\,000$
Question: Sofia and Maya use different methods to work out $4.56 \times 10^5$. Which method is clearer and why?
Equipment: Pencil, paper, calculator
Method:
Sofia’s method:
There are five zeros in $10^5$, so move the decimal point five places to the right.
There are three empty spaces, so fill them with zeros.
So, $4.56 \times 10^5 = 456000$
Maya’s method:
The number 4.56 has two decimal places.
The number $10^5$ has five zeros.
$5 - 2 = 3$, so I must add three zeros to the end of the number and remove the decimal point.
So, $4.56 \times 10^5 = 456000$
Follow-up Questions:
8. Work out:
a. $4.7 \times 10^{4}$
b. $91.5 \times 10^{3}$
c. $0.33 \times 10^{7}$
a. $47\,000$ b. $91\,500$ c. $3\,300\,000$
9. Copy these calculations and fill in the missing numbers.
a. $1.5 \times 10^{3} = \square$
b. $32.1 \times \square = 3\,210$
c. $\square \times 10^{5} = 612\,000$
d. $124.63 \times 10 \times \square = 12\,463\,000$
a. $1\,500$ b. $100$ c. $6.12$ d. $1\,000$
10. Copy and complete the working for each of the following.
a. $8000 + 10^{3} = 8000 + 1000 = \square$
b. $80\,500\,000 + 10^{5} = 80\,500\,000 + 100\,000 = \square$
a. $9\,000$ b. $80\,600\,000$
11. Marcus says: ‘When I divide a whole number by $10^{4}$, I just have to cross four zeros off the end of the number. When I divide a whole number by $10^{5}$, I just have to cross five zeros off the end of the number. This works for any positive whole number power.’
Is Marcus correct? Discuss in pairs or groups.
Yes, for whole numbers. Dividing a whole number by $10^{n}$ shifts its digits $n$ places to the right, which is the same as removing $n$ zeros from the end (e.g., $37\,000 \div 10^{3} = 37$). This rule is specific to whole numbers; numbers with decimals require moving the decimal point instead of just removing zeros.
12. Work out:
a. $80\,000 \div 10^{4}$
b. $510\,000 \div 10^{3}$
c. $8\,460\,000\,000 \div 10^{5}$
a. $8$ b. $510$ c. $84\,600$
Question: Sofia and Maya use different methods to work out $2\,350\,000 \div 10^5$. Which method do you think is more effective?
Equipment: Pencil, paper, calculator
Method:
Sofia’s method:
There are five zeros in $10^5$, so move the decimal point five places to the left.
The decimal point stops between the 3 and the 5.
So, $2\,350\,000 \div 10^5 = 23.5$
Maya’s method:
The number 2,350,000 has four zeros.
The number $10^5$ has five zeros.
$5 - 4 = 1$, so there must be one digit (non-zero) after the decimal point.
So, $2\,350\,000 \div 10^5 = 23.5$
Follow-up Questions:
14. Work out:
a. $230 \div 10^{1}$ b. $230 \div 10^{2}$ c. $230 \div 10^{3}$ d. $230 \div 10^{4}$
e. $65 \div 10^{1}$ f. $65 \div 10^{2}$ g. $65 \div 10^{3}$ h. $65 \div 10^{4}$
i. $9 \div 10^{1}$ j. $9 \div 10^{2}$ k. $9 \div 10^{3}$ l. $9 \div 10^{4}$
a. $23$ b. $2.3$ c. $0.23$ d. $0.023$
e. $6.5$ f. $0.65$ g. $0.065$ h. $0.0065$
i. $0.9$ j. $0.09$ k. $0.009$ l. $0.0009$
15. Choose the correct answer, A, B or C, for each of the following.
a. $6700000 \div 10^{5}$ A $670$ B $6.7$ C $0.67$
b. $9520 \div 10^{4}$ A $0.952$ B $9.52$ C $0.0952$
c. $18500000 \div 10^{6}$ A $185$ B $1.85$ C $18.5$
a. A ($670$) b. B ($9.52$) c. A ($185$)
16. These formulae show how to convert between some metric units of length.
Use the formulae to work out the missing numbers in these conversions:
a. $\square \ \text{mm} = 8 \ \text{cm}$
b. $\square \ \text{mm} = 15 \ \text{cm}$
c. $\square \ \text{mm} = 7 \ \text{m}$
d. $\square \ \text{mm} = 3.4 \ \text{m}$
e. $\square \ \text{mm} = 9 \ \text{km}$
f. $\square \ \text{mm} = 0.6 \ \text{km}$
g. $\square \ \text{mm} = 12.4 \ \text{cm}$
h. $\square \ \text{mm} = 32.25 \ \text{km}$
a. $80 \ \text{mm}$ b. $150 \ \text{mm}$ c. $7000 \ \text{mm}$ d. $3400 \ \text{mm}$
e. $9000000 \ \text{mm}$ f. $600000 \ \text{mm}$ g. $124 \ \text{mm}$ h. $32250000 \ \text{mm}$
17.
a. Convert $8000000 \ \text{mm}$ to km.
Unit conversions: Start by converting millimetres (mm) to centimetres (cm), then centimetres to metres (m), and finally metres to kilometres (km).
b. Write a formula that will convert a length in mm to a length in km.
c. Use your formula from part b to work out the missing numbers in these conversions:
i. $\square \ \text{km} = 90000000 \ \text{mm}$
ii. $\square \ \text{km} = 15600000 \ \text{mm}$
iii. $\square \ \text{km} = 770000 \ \text{mm}$
a. $8 \ \text{km}$
b. $\text{km} = \frac{\text{mm}}{10^{6}}$
c. i. $90 \ \text{km}$ ii. $15.6 \ \text{km}$ iii. $0.77 \ \text{km}$
18. a. Classify these number cards into groups of the same value. There should be one card left over.

b. Write two new cards that have the same value as the card that is left over.
a. Groupings vary, but one card (likely $0.00078 \times 10^{6}$) will be left over.
b. Example: $7.8 \times 10^{2}$ and $780 \times 10^{0}$
Now that you can multiply and divide whole numbers and decimals by positive powers of 10, you're ready to extend this understanding to negative powers. This will show how numbers smaller than 1 can also be expressed as powers of 10, linking decimals, fractions, and index notation into one clear pattern.
Look at this section of the decimal place-value table.
| ... | thousands | hundreds | tens | units | • | tenths | hundredths | thousandths | ... |
| ... | $1000$ | $100$ | $10$ | $1$ | • | $\frac{1}{10}$ | $\frac{1}{100}$ | $\frac{1}{1000}$ | ... |
You can write the numbers $10$, $100$, $1000$, … as positive powers of 10.
You can write the numbers $\frac{1}{10}$, $\frac{1}{100}$, $\frac{1}{1000}$, … as negative powers of 10.
Look at this pattern of numbers, written as powers of 10. Is there a link between the powers and the values?
..., $1000 = 10^3$, $100 = 10^2$, $10 = 10^1$, $1 = 10^0$, $\frac{1}{10} = 10^{-1}$, $\frac{1}{100} = 10^{-2}$, $\frac{1}{1000} = 10^{-3}$, ...
Decimals as fractions and powers of ten: You can write the decimal \(0.1\) as \(\frac{1}{10}\) or \(10^{-1}\). You can write the decimal \(0.01\) as \(\frac{1}{100}\) or \(10^{-2}\).
This pattern continues as the numbers get bigger and smaller.
For example, $10000 = 10^4$ and $\frac{1}{10000} = 10^{-4}$, $100000 = 10^5$ and $\frac{1}{100000} = 10^{-5}$.
It is important to remember these two key points:
1Multiplying a number by $\frac{1}{10}, \frac{1}{100}, \frac{1}{1000}, \frac{1}{10000}$ … is the same as dividing the same number by $10, 100, 1000, \dots$
2Dividing a number by $\frac{1}{10}, \frac{1}{100}, \frac{1}{1000}, \frac{1}{10000}$ … is the same as multiplying the same number by $10, 100, 1000, \dots$
19. Match each decimal with the correct fraction and power of $10$. The first one has been done for you: a, D and ii.
| Decimal | Fraction | Power of $10$ |
|---|---|---|
| $0.1$ | $\frac{1}{10}$ | $10^{-1}$ |
| $0.001$ | $\frac{1}{1000}$ | $10^{-3}$ |
| $0.00001$ | $\frac{1}{100000}$ | $10^{-5}$ |
| $0.01$ | $\frac{1}{100}$ | $10^{-2}$ |
| $0.0001$ | $\frac{1}{10000}$ | $10^{-4}$ |
a – D – ii ($0.1 = \frac{1}{10} = 10^{-1}$)
b – A – v ($0.001 = \frac{1}{1000} = 10^{-3}$)
c – E – iv ($0.00001 = \frac{1}{100000} = 10^{-5}$)
d – C – i ($0.01 = \frac{1}{100} = 10^{-2}$)
e – B – iii ($0.0001 = \frac{1}{10000} = 10^{-4}$)
20. Copy and complete
a. $3.2 \times 10^{3} = 3.2 \times 1000 = \ldots$
b. $3.2 \times 10^{2} = 3.2 \times 100 = \ldots$
c. $3.2 \times 10^{1} = 3.2 \times \ldots = \ldots$
d. $3.2 \times 10^{0} = 3.2 \times 1 = \ldots$
e. $3.2 \times 10^{-1} = 3.2 \div 10 = \ldots$
f. $3.2 \times 10^{-2} = 3.2 \div 100 = \ldots$
g. $3.2 \times 10^{-3} = 3.2 \div \ldots = \ldots$
h. $3.2 \times 10^{-4} = 3.2 \div \ldots = \ldots$
a. $3.2 \times 10^{3} = 3.2 \times 1000 = 3200$
b. $3.2 \times 10^{2} = 3.2 \times 100 = 320$
c. $3.2 \times 10^{1} = 3.2 \times 10 = 32$
d. $3.2 \times 10^{0} = 3.2 \times 1 = 3.2$
e. $3.2 \times 10^{-1} = 3.2 \div 10 = 0.32$
f. $3.2 \times 10^{-2} = 3.2 \div 100 = 0.032$
g. $3.2 \times 10^{-3} = 3.2 \div 1000 = 0.0032$
h. $3.2 \times 10^{-4} = 3.2 \div 10000 = 0.00032$
21. Look at your answers to Question $2$. Compare all your answers with the number you started with, $3.2$. Arun makes this conjecture.
When you multiply $3.2$ by $10$ to a negative power, the answer is always smaller than $3.2$.
a. Is Arun correct? Use specialising to explain your answer.
b. Copy and complete these generalising statements:
i. When you multiply a number by $10$ to a negative power, the answer is always ……… than the number you started with.
ii. When you multiply a number by $10$ to the power zero, the answer is always ……… as the number you started with.
iii. When you multiply a number by $10$ to a positive power, the answer is always ……… than the number you started with.
a. Yes. For any positive integer $n$, $10^{-n}=\dfrac{1}{10^{n}} \lt 1$, so $3.2 \times 10^{-n}$ is less than $3.2$ (e.g., $0.32$, $0.032$, $0.0032$ in Question $2$).
b. i. smaller ii. the same iii. greater
22. Work out:
a. $13 \times 10^{2}$ b. $7.8 \times 10^{3}$ c. $24 \times 10^{1}$
d. $8.55 \times 10^{4}$ e. $6.5 \times 10^{1}$ f. $0.08 \times 10^{5}$
g. $17 \times 10^{0}$ h. $8 \times 10^{-1}$ i. $8.5 \times 10^{-2}$
j. $4500 \times 10^{-4}$ k. $32 \times 10^{-3}$ l. $125 \times 10^{-2}$
a. $1300$ b. $7800$ c. $240$
d. $85500$ e. $65$ f. $8000$
g. $17$ h. $0.8$ i. $0.085$
j. $0.45$ k. $0.032$ l. $1.25$
23. Copy and complete:
a. $320 \div 10^{3} = 320 \div 1000 = \ldots$
b. $320 \div 10^{2} = 320 \div 100 = \ldots$
c. $320 \div 10^{1} = 320 \div \ldots = \ldots$
d. $320 \div 10^{0} = 320 \div 1 = \ldots$
a. $0.32$ b. $3.2$ c. $32$ d. $320$
24. Work out:
a. $27 \div 10^{1}$ b. $450 \div 10^{3}$ c. $36 \div 10^{2}$
d. $170 \div 10^{4}$ e. $0.8 \div 10^{1}$ f. $2480 \div 10^{5}$
g. $9 \div 10^{0}$ h. $0.25 \div 10^{2}$
a. $2.7$ b. $0.45$ c. $0.36$
d. $0.017$ e. $0.08$ f. $0.0248$
g. $9$ h. $0.0025$
Question: Two students use different methods to evaluate $2.6 \div 10^{-2}$. What do their methods show, and which approach would you choose for similar problems?
Equipment: Pencil, paper, calculator (optional)
Method (worked examples):
Cesar’s method
$10^{-2}=\dfrac{1}{10^2}=\dfrac{1}{100}$
$2.6 \div \dfrac{1}{100}=2.6 \times 100=260$
Domonique’s method
$2.6=\dfrac{26}{10}=26\times10^{-1}$
$(26\times10^{-1}) \div 10^{-2}=26\times\dfrac{10^{-1}}{10^{-2}}=26\times10^{-1-(-2)}=26\times10^{1}=260$
Follow-up prompts:
26. Copy and complete
a. $3.2 \div 10^{3} = 3.2 \div 1000 = \ldots$
b. $3.2 \div 10^{2} = 3.2 \div 100 = \ldots$
c. $3.2 \div 10^{1} = 3.2 \div \ldots = \ldots$
d. $3.2 \div 10^{0} = 3.2 \div 1 = \ldots$
e. $3.2 \div 10^{-1} = 3.2 \times 10 = \ldots$
f. $3.2 \div 10^{-2} = 3.2 \times 100 = \ldots$
g. $3.2 \div 10^{-3} = 3.2 \times \ldots = \ldots$
h. $3.2 \div 10^{-4} = 3.2 \times \ldots = \ldots$
a. $0.0032$ b. $0.032$ c. $3.2 \div 10 = 0.32$ d. $3.2$
e. $32$ f. $320$ g. $3.2 \times 1000 = 3200$ h. $3.2 \times 10000 = 32000$
27. Look at your answers to Question $8$. Compare all your answers with the number you started with, $3.2$. Zara makes this conjecture.
When you divide $3.2$ by $10$ to a negative power, the answer is always greater than $3.2$.
a. Is Zara correct? Use specialising to explain your answer.
b. Copy and complete these generalising statements:
i. When you divide a number by $10$ to a negative power, the answer is always ……… than the number you started with.
ii. When you divide a number by $10$ to the power zero, the answer is always ……… as the number you started with.
iii. When you divide a number by $10$ to a positive power, the answer is always ……… than the number you started with.
a. Yes. Since $10^{-n}=\dfrac{1}{10^{n}}\lt 1$, dividing by $10^{-n}$ is the same as multiplying by $10^{n}$, which makes the result larger (e.g., from Question $8$: $32$, $320$, $3200$, $32000$).
b. i. greater ii. the same iii. smaller
28. Work out:
a. $0.25 \div 10^{-1}$ b. $4.76 \div 10^{-4}$
c. $0.07 \div 10^{-3}$ d. $0.085 \div 10^{-2}$
a. $2.5$ b. $47600$ c. $70$ d. $8.5$
29. Copy this table, which contains a secret coded message.
| 3 | 3.3 | 0.3 | 3.3 | 300 | 33 | 6 | 6 | 0.6 | 0.3 | 0.33 | 3.3 | 0.3 | 33 | 300 | 0.06 | 33 | 60 | 33 | 0.03 | 600 | 33 | 300 |
Work out the answers to the calculations in the code box below. Find the answer in your secret code table. Write the letter from the code box above the number in your table.
| $0.6 \times 10^{2} = S$ | $60 \times 10^{-1} = L$ | $0.06 \div 10^{-1} = A$ | $600 \div 10^{0} = R$ | $60 \times 10^{-3} = H$ | $33 \div 10^{1} = O$ | $0.33 \times 10^{0} = Y$ | $300 \times 10^{-3} = N$ | $300 \div 10^{4} = C$ | $3300 \times 10^{-2} = E$ | $0.3 \div 10^{-3} = T$ | $300 \div 10^{2} = D$ |
Secret coded message: "HAPPY LEARNING!"
This is found by solving each number in the orange table using the green code box and writing the corresponding letter above each number.
Question: How does multiplying or dividing by powers of 10 affect the size of a number?
Equipment: Pencil, paper, calculator (optional)
Method:
31. Work out the missing power in each question in these spider diagrams.
In each part, all the questions in the outer shapes should give the answer in the centre shape.
a.

b.

a (centre = $8$):
$0.8 \times 10^{\color{black}{1}} = 8$, $8 \div 10^{\color{black}{0}} = 8$, $80 \times 10^{\color{black}{-1}} = 8$,
$0.08 \div 10^{\color{black}{-2}} = 8$, $0.008 \times 10^{\color{black}{3}} = 8$, $800 \div 10^{\color{black}{2}} = 8$
b (centre = $0.32$):
$32 \div 10^{\color{black}{2}} = 0.32$, $0.32 \times 10^{\color{black}{0}} = 0.32$, $3.2 \div 10^{\color{black}{1}} = 0.32$,
$320 \div 10^{\color{black}{3}} = 0.32$, $32 \times 10^{\color{black}{-2}} = 0.32$, $3.2 \times 10^{\color{black}{-1}} = 0.32$
Dividing by $10^{-n}$ makes the number bigger, not smaller. For example, $2.5 \div 10^{-3} = 2.5 \times 10^3 = 2500$. Remember: a negative index means a reciprocal, so dividing by it reverses the effect.