Physics A Level
Chapter 20: Ideal gases 20.3 Measuring gases
Physics A Level
Chapter 20: Ideal gases 20.3 Measuring gases
We are going to picture a container of gas, such as the box shown in Figure 20.4. There are four properties of this gas that we might measure: pressure, temperature, volume and mass. In this chapter, you will learn how these quantities are related to one another.
Figure 20.4: A gas has four measurable properties, which are all related to one another: pressure, temperature, volume and mass.
This is the normal force exerted per unit area by the gas on the walls of the container. We saw in Chapter 7 that molecular collisions with the walls of the container produce a force and thus create a pressure.
Pressure is measured in pascals, Pa $(1\,Pa = 1N\,{m^{ - 2}})$.
This might be measured in $^ \circ C$, but in practice it is more useful to use the thermodynamic (Kelvin) scale of temperature. You should recall how these two scales are related:
$T(K) = \theta {(^ \circ }C) + 273.15$
This is a measure of the space occupied by the gas. Volume is measured in ${m^3}$.
This is measured in g or kg. In practice, it is more useful to consider the amount of gas, measured in moles. The mole is the SI unit of substance, not a unit of mass.
We have seen in Chapter 15 that each atom or molecule has a mass in unified atomic mass units (u), approximately equal to the number of nucleons (protons and neutrons) it contains.
We have also seen that $1\,u\, = 1.66 \times {10^{ - 27}}\,kg$.
Thus, each atom of carbon-12 has a mass:
$\begin{array}{l}
12u = 12 \times 1.66 \times {10^{ - 27}}\,kg\\
= 1.99 \times {10^{ - 26}}\,kg
\end{array}$
So, $0.012 kg$ of carbon-12 contains $\frac{{0.012}}{{1.99 \times {{10}^{ - 26}}}} = 6.02 \times {10^{23}}$ molecules.
A mole of any substance (solid, liquid or gas) contains a standard number of particles (molecules or atoms). This number is known as the Avogadro constant, ${N_A}$. The value for ${N_A}$ is $6.02 \times {10^{23}}\,mo{l^{ - 1}}$. We can easily determine the number of atoms in a sample if we know how many moles it contains. For example:
$2.0 mol$ of helium contains
$2.0 \times 6.02 \times {10^{23}} = 1.20 \times {10^{24}}\,atoms$
$10 mol$ of carbon contains
$10 \times 6.02 \times {10^{23}} = 6.02 \times {10^{24}}\,atoms$
We will see later that, if we consider equal numbers of moles of two different gases under the same conditions, their physical properties are the same.
3) The mass of one atom of carbon-12 is $12 u$. Determine:
a: the mass of one atom of carbon-12 in kg, given that $1u = 1.66 \times {10^{ - 27}}\,kg$
b: the number of atoms and the number of moles in $54 g$ of carbon
c: the number of atoms in $1.0 kg$ of carbon.
4) a: Calculate the mass in grams of a single atom of uranium-235 of mass $235 u$.
b: A small pellet of uranium-235 has a mass of $20 mg$. For this pellet, calculate:
i- the number of uranium atoms
ii- the number of moles.
‘It can be useful to recall that $1.0 kg$ of ordinary matter contains in the order of 1026 atoms.’ Making suitable estimates, test this statement.